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hibernate里面实现复杂的查询

由于hibernate对sql的二次封装,使部分复杂的查询语句不能被执行,我列举两种解决方法,和大家讨论!

第一种:查询结果集

session session = this.getsession();
        list result = new arraylist();
        string strsql = "select buy.isbn,buy.bookname,buy.bookengname,count(*) as counum from (select distinct usee.isbn from stubasicinfo stu,teachingmaterialuse usee ";
        strsql = strsql
                + " where stu.identityid = usee.identityid and stu.deptid = '"
                + banji + "' and usee.academicyearcode='" + xn
                + "' and usee.semestercode = '" + xq
                + "') ddd,teachingmaterialbuyinto buy,teachingmaterialuse usee ";
        strsql = strsql
                + "where usee.isbn= ddd.isbn and usee.isbn= buy.isbn group by buy.isbn,buy.bookname,buy.bookengname";
        system.out.println(strsql);
        try
        {
            connection con = session.connection();
            statement statement = con.createstatement(resultset.type_scroll_insensitive,resultset.concur_read_only);
            resultset rs = statement.executequery(strsql);
            
            if (rs.next()) {
                while (!rs.isafterlast()) {
                    list templist = new arraylist();
                    templist.add(rs.getstring("isbn"));
                    templist.add(rs.getstring("bookname"));
                    templist.add(rs.getstring("bookengname"));
                    templist.add(rs.getstring("counum"));
                    result.add(templist);
                    rs.next();
                }
              }
        }catch (sqlexception e)
        {
            system.out.println("----" + e);
        }
        catch (hibernateexception e)
        {
            system.out.println("----" + e);
        }
        finally
        {
            this.closesessionifnecessary(session);
        }


第二种:使用session

session session = this.getsession();
        int acount = 0;
        try
        {
            string sqltext = "select count(*) from classroominfo room where room.flag='1' and room.type='"
                    + usertype + "' ";
            if ((name != null) && ((name != "null")))
            {
                sqltext = sqltext + " and room.name like '%" + name + "%' ";
            }
            else if ((buildingcode != null) && ((buildingcode != "null")))
            {
                sqltext = sqltext + " and room.buildingcode like '%"
                        + buildingcode + "%' ";
            }
            else if ((dept != null) && ((dept != "null")))
            {
                sqltext = sqltext + " and room.deptid ='" + dept + "' ";
            }

            acount = ((integer) session.iterate(sqltext).next()).intvalue();

        }
        catch (hibernateexception e)
        {
            system.out.println("hibernateexception" + e);
        }
        finally
        {
            this.closesessionifnecessary(session);
        }
        return acount;


这两种方法实际上都是使用hibernate的session实现!


 


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