本文主要讲述在midp1.0情况下处理开发过程遇到的连续按键事件,结合具体的实例给出一种实用的解决方案。
我们知道midp中的低级事件处理是通过keypressed()、keyreleased()和keyrepeated()来处理的,分别在按键被按下、释放和重复按键的时候被触发。当方法被调用的时候,系统会把所按下键的键值传递给上述的三个方法,根据按键的键值我们可以进行相关的处理。在midp中定义了如下的按键值分别是: key_num0, key_num1, key_num2, key_num3, key_num4, key_num5, key_num6, key_num7, key_num8, key_num9, key_star 和 key_pound。
在游戏开发中为了保证程序的可移植性,通常我们都会把键值转换为游戏动作,在midp中定义了如下的游戏动作: up, down, left, right, fire, game_a, game_b, game_c,game_d。转换非常简单,可以通过canvas提供的方法getgameaction()。
一般来说处理keypressed()和keyreleased()都比较容易,但是处理按键一直被按下的情况稍微复杂一些。因为我们使用的设备并不一定支持连续按键的事件。你可以通过方法hasrepeatevents()来检测平台是否支持当按键持续按下的时候产生重复事件。如果支持那么你可以在keyrepeated()的方法中处理相关逻辑,如果不支持那么你必须采取其他的方法。
这里笔者介绍一种通过设置标志位的方式来处理连续按键的方法。其实原理非常的简单,我们通过设置标志位判断按键是否被按下了,比如我们判断left是不是被按下了。当left被按下的时候,我们把成员变量leftpressed设置为true,代码如下:
public void keypressed(int keycode)
{
int action = getgameaction(keycode);
switch (action)
{
case left:
left();
leftpressed = true;
break;
case right:
right();
rightpressed = true;
break;
default:
break;
}
repaint();
}
public void keyreleased(int keycode)
{
int action = getgameaction(keycode);
switch (action)
{
case left:
leftpressed = false;
buttonpressed = "";
break;
case right:
rightpressed = false;
buttonpressed = "";
break;
default:
break;
}
repaint();
}
if (leftpressed)
{
left();
}
if (rightpressed)
{
right();
}
package com.j2medev;
import javax.microedition.lcdui.*;
import javax.microedition.midlet.midlet;
import javax.microedition.midlet.midletstatechangeexception;
public class keyactionmidlet extends midlet
{
private display display;
private maincanvas maincanvas;
protected void startapp() throws midletstatechangeexception
{
display = display.getdisplay(this);
maincanvas = new maincanvas();
new thread(maincanvas).start();
display.setcurrent(maincanvas);
}
protected void pauseapp()
{
}
protected void destroyapp(boolean arg0) throws midletstatechangeexception
{
}
}
package com.j2medev;
import javax.microedition.lcdui.*;
public class maincanvas extends canvas implements runnable
{
private string buttonpressed;
private boolean leftpressed;
private boolean rightpressed;
private int px = getwidth() / 2;
public final int py = getheight() / 2;
public maincanvas()
{
buttonpressed = " ";
}
private void left()
{
if (px >= 0)
{
px--;
}
buttonpressed = "left";
repaint();
}
private void right()
{
if (px <= getwidth())
{
px++;
}
buttonpressed = "right";
repaint();
}
public void run()
{
while (true)
{
if (leftpressed)
{
left();
}
if (rightpressed)
{
right();
}
try
{
thread.sleep(50);
} catch (interruptedexception e)
{
e.printstacktrace();
}
}
}
public void paint(graphics g)
{
g.setcolor(0xffffff);
g.fillrect(0, 0, getwidth(), getheight());
g.setcolor(0x000000);
g.drawstring(buttonpressed, 20, 20, graphics.left graphics.top);
g.drawstring("j2me", px, py, graphics.hcenter graphics.top);
}
public void keyreleased(int keycode)
{
int action = getgameaction(keycode);
switch (action)
{
case left:
leftpressed = false;
buttonpressed = "";
break;
case right:
rightpressed = false;
buttonpressed = "";
break;
default:
break;
}
repaint();
}
public void keypressed(int keycode)
{
int action = getgameaction(keycode);
switch (action)
{
case left:
left();
leftpressed = true;
break;
case right:
right();
rightpressed = true;
break;
default:
break;
}
repaint();
}
public void keyrepeated(int keycode)
{
int action = getgameaction(keycode);
switch (action)
{
case left:
left();
break;
case right:
right();
break;
default:
break;
}
repaint();
}
}
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